-7(x)=-4x^2+19

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Solution for -7(x)=-4x^2+19 equation:



-7(x)=-4x^2+19
We move all terms to the left:
-7(x)-(-4x^2+19)=0
We get rid of parentheses
4x^2-7x-19=0
a = 4; b = -7; c = -19;
Δ = b2-4ac
Δ = -72-4·4·(-19)
Δ = 353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{353}}{2*4}=\frac{7-\sqrt{353}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{353}}{2*4}=\frac{7+\sqrt{353}}{8} $

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